a³ − b³ and a³ + b³ Formula: Proof, Examples & Common Mistakes

a^3 - b^3 formula

The a^3 – b^3 formula is (a – b) (a^2 + ab + b^2). This formula is used to calculate the difference of two cubes.

Cube Formulas at a Glance

ExpressionFormulaName
a3 − b3(a − b)(a2 + ab + b2)Difference of two cubes
a3 + b3(a + b)(a2 − ab + b2)Sum of two cubes
(a + b)3a3 + 3a2b + 3ab2 + b3Cube of a sum
(a − b)3a3 − 3a2b + 3ab2 − b3Cube of a difference

Tip to remember the signs: in both a3 − b3 and a3 + b3, the first bracket has the same sign as the question, and the middle term (ab) of the second bracket has the opposite sign. The last term (b2) is always positive.

What is a^3-b^3 Formula?

The a3-b3 formula is (a – b) (a2 + ab + b2)

Prove a Cube Minus b Cube Formula (a^3-b^3)

Let’s prove a cube minus b cube formula. To prove that a3 – b3 = (a – b) (a2 + ab + b2).

LHS = RHS

LHS = a3 – b3

On Solving RHS side we get,

= (a – b) (a2 + ab + b2)

On multiplying a and b separately with (a2 + ab + b2)

= a (a2 + ab + b2) – b(a2 + ab + b2)
= a3 + a2b + ab2 – a2b – ab2 – b3
= a3 + a2b – a2b + ab2– ab2 – b3
= a3 – 0 – 0 – b3
= a3 – b3

Hence proved, LHS = RHS

a3 + b3 Formula (A Cube Plus B Cube)

The a3 + b3 formula is a3 + b3 = (a + b)(a2 − ab + b2). It is used to factorise the sum of two cubes.

Proof of a3 + b3 Formula

Start with the right-hand side and multiply each term of (a + b) with (a2 − ab + b2):

(a + b)(a2 − ab + b2)
= a(a2 − ab + b2) + b(a2 − ab + b2)
= a3 − a2b + ab2 + a2b − ab2 + b3
= a3 + b3

The middle terms cancel out, so LHS = RHS. Hence proved.

Example: Find 53 + 33 Using the a3 + b3 Formula

Let a = 5 and b = 3.
a3 + b3 = (a + b)(a2 − ab + b2)
= (5 + 3)(25 − 15 + 9)
= 8 × 19
= 152
Check: 53 + 33 = 125 + 27 = 152 ✔

Example: Find 113 + 93

Let a = 11 and b = 9.
(a + b)(a2 − ab + b2) = (11 + 9)(121 − 99 + 81) = 20 × 103 = 2060
Check: 1331 + 729 = 2060 ✔

(a + b)3 and (a − b)3 Formulas

Students often confuse a3 + b3 with (a + b)3. They are different:

  • (a + b)3 = a3 + b3 + 3ab(a + b) = a3 + 3a2b + 3ab2 + b3
  • (a − b)3 = a3 − b3 − 3ab(a − b) = a3 − 3a2b + 3ab2 − b3
  • So a3 + b3 = (a + b)3 − 3ab(a + b) and a3 − b3 = (a − b)3 + 3ab(a − b)

Example: if a = 2 and b = 3, then (a + b)3 = 53 = 125, while a3 + b3 = 8 + 27 = 35. The difference is 3ab(a + b) = 3 × 2 × 3 × 5 = 90 ✔

Prove that (a + b + c)3 − a3 − b3 − c3 = 3(a + b)(b + c)(c + a)

Group the terms as [(a + b + c)3 − a3] − [b3 + c3].

Step 1: Use the a3 − b3 formula with x = (a + b + c) and y = a:
(a + b + c)3 − a3 = (b + c)[(a + b + c)2 + a(a + b + c) + a2]

Step 2: Use the a3 + b3 formula:
b3 + c3 = (b + c)(b2 − bc + c2)

Step 3: Take (b + c) common:
= (b + c)[(a + b + c)2 + a(a + b + c) + a2 − b2 + bc − c2]

Step 4: Expand the bracket:
(a2 + b2 + c2 + 2ab + 2bc + 2ca) + (a2 + ab + ac) + a2 − b2 + bc − c2
= 3a2 + 3ab + 3ac + 3bc
= 3(a2 + ab + ac + bc)
= 3(a + b)(a + c)

Step 5: So (a + b + c)3 − a3 − b3 − c3 = (b + c) × 3(a + b)(a + c) = 3(a + b)(b + c)(c + a). Hence proved.

Examples on a^3-b^3 Formula

Here are a some examples on a3-b3.

Example 1: Find the Value of 833-533 Using the a^3-b^3 Formula.

Solution:

To find 833− 533 using the a3−b3 formula:

Let us assume that a = 83 and b = 53

Apply a3−b3 formula: a3 – b3 = (a – b) (a2 + ab + b2)

(83−53)(832+(83×53)+532)

=(83-53)(832+4399+532)

=(83-53)(6889+4399+2809)

=(30) (14097)

Now, multiply (a – b) by (a2 + ab + b2)

= 422910

Therefore, 833−533=422910

Example 2: Simplify 19^3-20^3 Using a Cube Minus b Cube Formula

Solution

To find 19^3 – 20^3

Let us assume a = 19 and b = 20

Using formula a3 – b3 = (a – b) (a2 + ab + b2)

a3 – b3 = (a – b) (a2 + ab + b2)

193 – 203 = (19 – 20) (192 + (19)(20) + 202)

= (-1) (361 + 380 + 400)

= (-1) (1141)

= -1141

Therefore, 19^3-20^3 = -1141

Common Mistakes to Avoid

  • Writing a3 − b3 = (a − b)3. This is wrong: for a = 3, b = 1, a3 − b3 = 26 but (a − b)3 = 8.
  • Writing the second bracket as (a2 − ab + b2) for a3 − b3. The middle sign must be +ab for a difference of cubes.
  • Writing (a2 + b2) and forgetting the ab term completely.
  • Mixing up a3 + b3 (sum of cubes) with (a + b)3 (cube of a sum).

FAQ’s Related a^3-b^3 Formula

What is the Expansion of a3 – b3 Formula?

a3– b3 formula is read as a cube minus b cube. The a3– b3 expansion is expressed as (a – b) (a2 + ab + b2).

What is the Formula for a^3-b^3?

The formula for a^3 – b^3 is (a – b) (a^2 + ab + b^2)

What is a3 – b3 Formula in Algebra?

The formula for a3-b3 in algebra is a^3- b^3= (a – b) (a^2 + ab + b^2). This formula is used for factoring and simplifying the expressions involving the difference of two cubes.

What are a^3 – b^3 and a^3 + b^3 Formulas?

The formula of a3-b3 = (a – b) (a2 + ab + b2)
The formula for a3+b3 = (a + b)(a2 – ab + b2)

What is a Cube Minus b Cube Formula?

The formula of a Cube Minus b Cube is a3-b3 = (a – b) (a2 + ab + b2)

Also Read:

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