if we want to solve 4x^{2}-5x-12=0 then we can use the quadratic formula, which is given by:

Once in standard form, identify a, b and c from the original equation and Put them into the quadratic formula.

a=4 , b=4 and c=-12

Separate the equations:

## Factor 4x^2-5x-12=0 Quadratic Equation?

Use quadratic equation

x=-b±√b^{2}-4ac/2a

Let’s Assume a = 4, b = -5, and c = -12 (Put the a b c value in formula)

x=-(-5)±√(-5)^{2}-4.4.-12/2.4

*Simplify the expression* x=5±√217/8

*Separate the equations*

x=√217+5/8

x=-√217+5/8

## What is the Graph for 4x^{2}-5x-12=0 ?

Here we are provide Graph for 4x^{2}-5x-12=0

## FAQ

### What is the 4×2-5x-12 0 Quadratic Formula?

**4x 2 5x 12 0 quadratic formula** is x=-b±√b^{2}-4ac/2a

### What is 4x^{2}-5x+12=0 Discriminant?

The discriminant is the part of the quadratic formula under the radical, which is ** denoted by b2−4ac**.

Let’s Put the values in formula b2-4ac.

a = 4, b = -5, and c = 12

b^{2}−4ac=(−5)^{2}−4⋅4⋅12

b^{2}−4ac=167