x2+(y-3√2x)2=1 What is the Value of This Equation​ and Graph

x2+(y-3√2x)2=1

What is the Value of this Equation​ x2+(y-3√2x)2=1

Answer:

Given Equation is x2+(y-3√2x)2=1

Now Subtract X2 from both sides of the equation (Means is that minus X2 from LHS and RHS side)

(y-3√2x)2+x2-x2=1-x2

Subtracting x2 from itself leave 0

(y-3√2x)2=1-x2

Now take square root of both sides of equation

(y-3√2x)2=√1-x2

The square root operation always results is one positive number and one negative number.

(y-3√2x)=√1-x2

(y-3√2x)=-√1-x2

now take-3√2x from the right side then the value of is : y=√1-x2+3√2x and y=-√1-x2+3√2x

Hance: Value of This Equation​ is

What is the Graph of x^2+(y-3√x^2)^2=1 ?

Graph of x^2+(y-3√x^2)^2=1
Graph of x^2+(y-3√x^2)^2=1

x2+(y-3√x2)2=1 Meaning

The equation x^2 + (y – 3√x^2)^2 = 1 represents a certain geometric figure called an ellipse.

Here is meaning of x2+(y-3√x2)2=1

x^2 and (y – 3√x^2)^2:

These terms represent the squared distances from the center of the ellipse to the points on the curve along the x-axis and y-axis, respectively. However, the presence of the term 3√x^2 in the y term indicates a shift and scaling compared to the standard ellipse equation.

= 1:

This equation defines a limit for all points that fulfill the condition. These points form a closed curve, namely the ellipse.

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